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The general solution of the differential equation dydx=ex+y\frac{dy}{dx} = e^{x+y}, is :

Solution

✅ Correct Option: 3

dydx=ex⋅ey\frac{dy}{dx} = e^x \cdot e^y. Separate variables: e−y dy=ex dxe^{-y} \, dy = e^x \, dx.

Integrate: −e−y=ex+c1-e^{-y} = e^x + c_1.

Rearranging: ex+e−y=ce^x + e^{-y} = c (where c=−c1c = -c_1).

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