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A piece of machinery is bought for Rs. 50,000. In the first year, it depreciates by 15%, and in each subsequent year, the depreciation rate increases by 5% from the previous year. The value of machinery after 3 years will be:

Solution

✅ Correct Option: 3

Initial value of machinery: Rs. 50,000

Depreciation rate in Year 1: 15%

Depreciation rate increases by 5% each subsequent year.


Year 1 depreciation: 15%

Remaining value percentage: 100% - 15% = 85%

Value after Year 1:

=50,000×85100= 50,000 \times \dfrac{85}{100}

=50,000×0.85= 50,000 \times 0.85

=42,500= 42,500


Year 2 depreciation: 15% + 5% = 20%

Remaining value percentage: 100% - 20% = 80%

Value after Year 2:

=42,500×80100= 42,500 \times \dfrac{80}{100}

=42,500×0.80= 42,500 \times 0.80

=34,000= 34,000


Year 3 depreciation: 20% + 5% = 25%

Remaining value percentage: 100% - 25% = 75%

Value after Year 3:

=34,000×75100= 34,000 \times \dfrac{75}{100}

=34,000×0.75= 34,000 \times 0.75

=25,500= 25,500


Alternatively, the value can be calculated directly:

Value after 3 years:

=50,000×0.85×0.80×0.75= 50,000 \times 0.85 \times 0.80 \times 0.75

=25,500= 25,500

Therefore, the value of machinery after 3 years is Rs. 25,500.

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