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Let AA be a non singular matrix of order n×nn \times n, Then ∣adj (3A)∣|\text{adj }(3A)| is equal to:

Solution

✅ Correct Option: 2

For any matrix BB of order n×nn \times n:

∣adj(B)∣=∣B∣n−1|\text{adj}(B)| = |B|^{n-1}

For any scalar kk and matrix AA of order n×nn \times n:

∣kA∣=kn∣A∣|kA| = k^n|A|


Finding ∣3A∣|3A|:

∣3A∣=3n∣A∣|3A| = 3^n|A|


Applying the adjoint formula with B=3AB = 3A:

∣adj(3A)∣=∣3A∣n−1|\text{adj}(3A)| = |3A|^{n-1}


Substituting ∣3A∣=3n∣A∣|3A| = 3^n|A|:

∣adj(3A)∣=(3n∣A∣)n−1|\text{adj}(3A)| = (3^n|A|)^{n-1}

=(3n)n−1×(∣A∣)n−1= (3^n)^{n-1} \times (|A|)^{n-1}

=3n(n−1)×∣A∣n−1= 3^{n(n-1)} \times |A|^{n-1}


Therefore, ∣adj(3A)∣=3n(n−1)∣A∣n−1|\text{adj}(3A)| = 3^{n(n-1)}|A|^{n-1}

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