CUET Mathematics - Let A = [a_ij]_n x n be a matrix, then match List-I with List-II Choose the correct answer from the options given below: | PYQs + Solutions

CUET Mathematics 2025 30 May Shift 1

Algebra

Easy

common

(A) - (IV), (B) - (III), (C) - (I), (D) - (II)

(A) - (IV), (B) - (III), (C) - (II), (D) - (I)

(A) - (III), (B) - (I), (C) - (IV), (D) - (II)

(A) - (III), (B) - (IV), (C) - (I), (D) - (II)

✅ Correct Option: 4

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If $A = \begin{bmatrix} 1 & 2 & 3 \\ -4 & -5 & -2 \end{bmatrix}$ , $B = \begin{bmatrix} 2 & -3 \\ 4 & -5 \\ 2 & -1 \end{bmatrix}$ and $BA = [b_{ij}]$ , then $(b_{23} - b_{31})$ is equal to

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Let $A = [a_{ij}]$ is given by $A = \begin{bmatrix} 1 & -1 & 2 \\ 3 & 4 & -5 \\ 2 & -1 & 3 \end{bmatrix}$ . Then the matrix $B = [b_{ij}]$ , where $b_{ij}$ = Minor of $a_{ij}$ is:

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If $A$ is an invertible matrix of order 3, then

Match List-I with List-II

List-I	List-II
(A) $\|\text{adj} A\|$	(I) $8\|A\|$
(B) $\|A(\text{adj} A)\|$	(II) $\|A\|^2$
(C) $\|2A\|$	(III) $\frac{1}{\|A\|}$
(D) $\|A^{-1}\|$	(IV) $\|A\|^3$

Choose the correct answer from the options given below:

List-I	List-II
(A) $\|\text{adj} A\|$	(I) $8\|A\|$
(B) $\|A(\text{adj} A)\|$	(II) $\|A\|^2$
(C) $\|2A\|$	(III) $\frac{1}{\|A\|}$
(D) $\|A^{-1}\|$	(IV) $\|A\|^3$

CUET Mathematics 2025 30 May Shift 1 PYQs

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