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Let A=[aij]n×nA = [a_{ij}]_{n \times n} be a matrix, then match List-I with List-II

List-IList-II
(A) ∣A∣=0\vert A\vert = 0(I) AA is a symmetric matrix
(B) ∣A∣≠0\vert A\vert \neq 0(II) AA is a skew-symmetric matrix
(C) AT=AA^T = A(III) AA is a singular matrix
(D) AT=−AA^T = -A(IV) AA is a non-singular matrix

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 4

∣A∣=0|A| = 0 means the determinant is zero, which is the definition of a singular matrix.

(A)→(III)(A) \rightarrow (III)


∣A∣≠0|A| \neq 0 means the determinant is non-zero, which is the definition of a non-singular matrix.

(B)→(IV)(B) \rightarrow (IV)


AT=AA^T = A means the transpose equals the matrix itself, which is the definition of a symmetric matrix.

(C)→(I)(C) \rightarrow (I)


AT=−AA^T = -A means the transpose equals the negative of the matrix, which is the definition of a skew-symmetric matrix.

(D)→(II)(D) \rightarrow (II)


Final matching:

(A)→(III)(A) \rightarrow (III)

(B)→(IV)(B) \rightarrow (IV)

(C)→(I)(C) \rightarrow (I)

(D)→(II)(D) \rightarrow (II)

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