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If y=12x(3x2+2)y = \sqrt{12^x(3x^2+2)}, then dydx\dfrac{dy}{dx} will be

(consider log⁡ex=log⁡x\log_e x = \log x)

Solution

✅ Correct Option: 2

Square first: y2=12x(3x2+2)y^2 = 12^x(3x^2+2).

Differentiating, 2ydydx=12xlog⁡12 (3x2+2)+12x(6x)2y\frac{dy}{dx} = 12^x\log 12\,(3x^2+2) + 12^x(6x).

Hence dydx=12x((3x2+2)log⁡12+6x)2y\frac{dy}{dx} = \dfrac{12^x((3x^2+2)\log 12 + 6x)}{2y}.

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