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Match the LIST-I with LIST-II

LIST-ILIST-II
A.In a binomial distribution, if n=16n = 16, p=0.75p = 0.75, then the mean isI.44
B.In a binomial distribution, if n=25n = 25, p=15p = \dfrac{1}{5}, then variance isII.3232
C.In a binomial distribution, the mean is 8 and the variance is 6, then the number of trials isIII.1818
D.If the mean and variance of a binomial distribution are 6 and 4 respectively, then the number of trials isIV.1212

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 2

A: mean =np=16(0.75)=12=np=16(0.75)=12 (IV).

B: variance =npq=25⋅15⋅45=4=npq=25\cdot\frac{1}{5}\cdot\frac{4}{5}=4 (I).

D: q=46=23q=\frac{4}{6}=\frac{2}{3}, so p=13p=\frac{1}{3} and n=61/3=18n=\frac{6}{1/3}=18 (III).

C then takes the remaining value 3232 (II).

Note: Item C supplies only the variance, which alone does not fix the number of trials; it has been matched by elimination.

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