Particular solution of the differential equation dy = e^2x+ydx, y(0) = 0 is: Option 1: y = |23-e^2x| Option 2: y = (3-e^2x) Option 3: y = 23-e^2x Option 4: y = 3-e^2x

The answer is 'y = |23-e^2x|'. View full solution:

CUET Mathematics - Particular solution of the differential equation dy = e^2x+ydx, y(0) = 0 is: | PYQs + Solutions

CUET Mathematics 2026 22nd May Shift 2

Calculus

Medium

core

$y = \log\left|\frac{2}{3-e^{2x}}\right|$

$y = \log(3-e^{2x})$

$y = \frac{2}{3-e^{2x}}$

$y = 3-e^{2x}$

✅ Correct Option: 1

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