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The tangent to the curve y=e3xy = e^{3x} at the point (0,1)(0, 1), meets the x-axis at :

Solution

✅ Correct Option: 3

dydx=3e3x\frac{dy}{dx} = 3e^{3x}. At (0,1)(0,1), slope =3= 3. Tangent: y−1=3(x−0)y - 1 = 3(x - 0), i.e. y=3x+1y = 3x + 1. For x-axis, y=0⇒x=−13y = 0 \Rightarrow x = -\frac{1}{3}. Point is (−13,0)\left(-\frac{1}{3}, 0\right).

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