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The function f(x)=x4−2x2f(x) = x^4 - 2x^2 is increasing on

Solution

✅ Correct Option: 1

A function is increasing when the derivative is positive: f′(x)>0f'(x) > 0.


Given f(x)=x4−2x2f(x) = x^4 - 2x^2

Using the power rule:

f′(x)=4x3−4xf'(x) = 4x^3 - 4x

Factoring:

f′(x)=4x(x2−1)f'(x) = 4x(x^2 - 1)

f′(x)=4x(x−1)(x+1)f'(x) = 4x(x - 1)(x + 1)


Setting f′(x)=0f'(x) = 0:

4x(x−1)(x+1)=04x(x - 1)(x + 1) = 0

Critical points: x=−1,x=0,x=1x = -1, x = 0, x = 1

These points divide the number line into 4 intervals.


Testing the sign of f′(x)=4x(x−1)(x+1)f'(x) = 4x(x - 1)(x + 1) in each interval:

IntervalTest PointSign of 4xSign of (x-1)Sign of (x+1)Sign of f'(x)Increasing?
x<−1x < -1x=−2x = -2----No
−1<x<0-1 < x < 0x=−0.5x = -0.5--++Yes
0<x<10 < x < 1x=0.5x = 0.5+-+-No
x>1x > 1x=2x = 2++++Yes

The derivative is positive on (−1,0)(-1, 0) and (1,∞)(1, \infty).


The function is increasing on (−1,0)∪(1,∞)(-1, 0) \cup (1, \infty).

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