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Mr. 'X' wishes to purchase a house for ₹ 49,65,000 with a down payment of ₹ 15,00,000 and balance amount in EMI for 25 years. If bank charges 6% per annum compounded monthly. Then the EMI is: [Given that (1.005)300=4.4650](1.005)^{300} = 4.4650]

Solution

✅ Correct Option: 4

The house price is ₹49,65,000 with a down payment of ₹15,00,000.

Loan Amount = ₹49,65,000 - ₹15,00,000 = ₹34,65,000


Given information:

Principal (P) = ₹34,65,000

Time = 25 years = 25 × 12 = 300 months

Annual Interest Rate = 6%

Monthly Interest Rate (r) = 6% ÷ 12 = 0.5% = 0.005

(1.005)300=4.4650(1.005)^{300} = 4.4650


The EMI formula is:

EMI=P×r×(1+r)n(1+r)n−1EMI = \frac{P \times r \times (1+r)^n}{(1+r)^n - 1}

Substituting the values:

EMI=34,65,000×0.005×(1.005)300(1.005)300−1EMI = \frac{34,65,000 \times 0.005 \times (1.005)^{300}}{(1.005)^{300} - 1}

EMI=34,65,000×0.005×4.46504.4650−1EMI = \frac{34,65,000 \times 0.005 \times 4.4650}{4.4650 - 1}


Simplifying the numerator:

34,65,000×0.005=17,32534,65,000 \times 0.005 = 17,325

17,325×4.4650=77,355.37517,325 \times 4.4650 = 77,355.375

Simplifying the denominator:

4.4650−1=3.46504.4650 - 1 = 3.4650


EMI=77,355.3753.4650EMI = \frac{77,355.375}{3.4650}

EMI=22,325EMI = 22,325

Therefore, the EMI is ₹22,325.

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