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A swimmer whose speed in still water is 6 km/hr, swims between two points in a river and returns to the starting point. He took 20 minutes more to cover the distance upstream than downstream. If the speed of the stream is 3 km/hr, then the distance between the two points is:

Solution

✅ Correct Option: 4

The swimmer's speed in still water is 6 km/hr and the stream speed is 3 km/hr.

When swimming downstream (with the current), the speeds add:

Downstream speed =6+3=9= 6 + 3 = 9 km/hr

When swimming upstream (against the current), the speeds subtract:

Upstream speed =6−3=3= 6 - 3 = 3 km/hr


The extra time taken upstream is 20 minutes.

Converting to hours:

2020 minutes =2060=13= \dfrac{20}{60} = \dfrac{1}{3} hour


Let the distance between the two points be dd km.

Time =DistanceSpeed= \dfrac{\text{Distance}}{\text{Speed}}

Time to go upstream =d3= \dfrac{d}{3} hours

Time to go downstream =d9= \dfrac{d}{9} hours

The upstream time is 13\dfrac{1}{3} hour more than the downstream time:

d3−d9=13\dfrac{d}{3} - \dfrac{d}{9} = \dfrac{1}{3}


Converting to a common denominator of 9:

3d9−d9=13\dfrac{3d}{9} - \dfrac{d}{9} = \dfrac{1}{3}

2d9=13\dfrac{2d}{9} = \dfrac{1}{3}

2d×3=9×12d \times 3 = 9 \times 1

6d=96d = 9

d=96d = \dfrac{9}{6}

d=1.5d = 1.5 km

Therefore, the distance between the two points is 1.5 km.

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