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If matrices A=[123]A = [1 \quad 2 \quad 3] and B=[123]B = \begin{bmatrix} 1 \\ 2 \\ 3 \end{bmatrix}, then BABA is equal to:

Solution

✅ Correct Option: 3

Given:

Matrix A=[123]A = [1 \quad 2 \quad 3] is a row matrix (1×3 matrix)

Matrix B=[123]B = \begin{bmatrix} 1 \\ 2 \\ 3 \end{bmatrix} is a column matrix (3×1 matrix)


For matrix multiplication BABA, the number of columns in BB equals the number of rows in AA (both are 1).

The multiplication is valid and results in a 3×3 matrix.


BA=[123]×[123]BA = \begin{bmatrix} 1 \\ 2 \\ 3 \end{bmatrix} \times [1 \quad 2 \quad 3]

Each element in BB multiplies with the entire row AA:

Row 1: 1×[123]=[123]1 \times [1 \quad 2 \quad 3] = [1 \quad 2 \quad 3]

Row 2: 2×[123]=[246]2 \times [1 \quad 2 \quad 3] = [2 \quad 4 \quad 6]

Row 3: 3×[123]=[369]3 \times [1 \quad 2 \quad 3] = [3 \quad 6 \quad 9]


BA=[123246369]BA = \begin{bmatrix} 1 & 2 & 3 \\ 2 & 4 & 6 \\ 3 & 6 & 9 \end{bmatrix}

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