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In a game of 100 points, A can give 20 points to B and 28 points to C. How many points can B give C?

Solution

✅ Correct Option: 1

In a game of 100 points, when A can give 20 points to B, it means when A finishes with 100 points, B has only 80 points. Similarly, when A can give 28 points to C, C has only 72 points when A reaches 100.

When A scores 100 points:

  • B scores 80 points
  • C scores 72 points

To find how many points B can give C, we need to determine C's score when B reaches 100 points.

The ratio of A to B is:

A:B=100:80=5:4A : B = 100 : 80 = 5 : 4

When B scores 100 points, A would score:

A=1004×5=125A = \dfrac{100}{4} \times 5 = 125 points


The ratio of A to C is:

A:C=100:72=25:18A : C = 100 : 72 = 25 : 18

When A scores 125 points, C would score:

C=12525×18C = \dfrac{125}{25} \times 18

C=5×18C = 5 \times 18

C=90C = 90 points


When B scores 100 points, C scores 90 points.

Points B can give to C =100−90=10= 100 - 90 = 10

Therefore, B can give C 10 points.

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