Given:
M=2−13 (column vector, 3×1)
N=[71−4] (row vector, 1×3)
To find (MN)T, first multiply M and N.
Multiplying a (3×1) matrix with a (1×3) matrix gives a (3×3) matrix.
Each element in M multiplies with the entire row N:
MN=2−13[71−4]
Row 1: 2×7=14, 2×1=2, 2×(−4)=−8
Row 2: (−1)×7=−7, (−1)×1=−1, (−1)×(−4)=4
Row 3: 3×7=21, 3×1=3, 3×(−4)=−12
MN=14−7212−13−84−12
The transpose swaps rows and columns.
Row 1 becomes Column 1, Row 2 becomes Column 2, Row 3 becomes Column 3:
(MN)T=142−8−7−14213−12
Therefore, (MN)T=142−8−7−14213−12