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In the given figure, feasible region represented by the constraints 4x+y≥804x + y \geq 80, x+5y≥115x + 5y \geq 115, 3x+2y≤1503x + 2y \leq 150, x,y≥0x,y \geq 0 is

Figure for CUET Mathematics 2025 13 May Shift 1 question 7 (Algebra)

Solution

✅ Correct Option: 3

The constraints are 4x+y≥804x + y \geq 80, x+5y≥115x + 5y \geq 115, 3x+2y≤1503x + 2y \leq 150, and x,y≥0x,y \geq 0.

Each constraint defines a region in the coordinate plane.


For 4x+y≥804x + y \geq 80:

The boundary line is 4x+y=804x + y = 80

Testing the origin (0,0)(0,0): 4(0)+0=0≥804(0) + 0 = 0 \geq 80 is false.

The feasible region is on the opposite side from the origin (above the line).


For x+5y≥115x + 5y \geq 115:

The boundary line is x+5y=115x + 5y = 115

Testing the origin (0,0)(0,0): 0+5(0)=0≥1150 + 5(0) = 0 \geq 115 is false.

The feasible region is on the opposite side from the origin (above the line).


For 3x+2y≤1503x + 2y \leq 150:

The boundary line is 3x+2y=1503x + 2y = 150

Testing the origin (0,0)(0,0): 3(0)+2(0)=0≤1503(0) + 2(0) = 0 \leq 150 is true.

The feasible region includes the origin side (below the line).


For x,y≥0x, y \geq 0:

The feasible region is in the first quadrant.


The feasible region satisfies all constraints simultaneously:

  • Above the line 4x+y=804x + y = 80
  • Above the line x+5y=115x + 5y = 115
  • Below the line 3x+2y=1503x + 2y = 150
  • In the first quadrant

The intersection of these regions forms a bounded polygonal region.

Based on the constraint directions, the feasible region is Region C.


Therefore, the answer is Option 3 (Region C).

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