The absolute maximum value of the function f(x) = 4x - 1/2x^2 in the interval [-2, 9/2] is Option 1: 10 Option 2: 9 Option 3: 8 Option 4: 6

The answer is '8'. View full solution:

CUET Mathematics 2025 - The absolute maximum value of the function f(x) = 4x - 1/2x^2 in the interval [-2, 9/2] is | PYQs + Solutions

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The demand for a certain product is represented by the function $p = 300 + 25x - x^2$ (in rupees), where x is the number of units demanded and p is the price per unit, then the marginal revenue when 15 units are sold, is

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If the function $f(x) = 2x^3 + 9x^2 + 12x-1$ is given,then $f(x)$ have

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2026: 25th May Shift 1

A particle moves along a curve $3y^2 = 6x^3 + 8$ such that its y-coordinate is changing at the rate of 9 cm/sec at point (1,2). Then the rate of a change of x-coordinate at the same point is :

2026: 21st May Shift 2

Consider the function $f(x) = -2x^3 + 3x^2 + 36x - 15$ , then which of the following are TRUE?

A. $f(x)$ increases on $(-2, 3)$

B. $f(x)$ decreases on $(-\infty, -2) \cup (3, \infty)$

C. $f(x)$ increases on $(-\infty, -2) \cup (3, \infty)$

D. $f(x)$ neither increases nor decreases on $(-2, 3)$

Choose the correct answer from the options given below:

2026: 21st May Shift 1

Given a function $f(x) = ax + \frac{b}{x}$ ; $a > 0, b > 0$ , then

Match List-I with List-II

List-I	List-II
(A) $f(x)$ has local maxima at $x$ is equal to	(I) $\sqrt{\frac{b}{a}}$
(B) $f(x)$ has local minima at $x$ is equal to	(II) $2\sqrt{ab}$
(C) Local Maxima of $f(x)$	(III) $-\sqrt{\frac{b}{a}}$
(D) Local Minima of $f(x)$	(IV) $-2\sqrt{ab}$

Choose the correct answer from the options given below:

The absolute maximum value of the function $f(x) = 4x - \frac{1}{2}x^2$ in the interval $\left[-2, \frac{9}{2}\right]$ is

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