CUET Mathematics - The general solution of the differential equation _e(dy/dx) = ax + by is | PYQs + Solutions

CUET Mathematics 2025 13 May Shift 1

Calculus

Medium

common

$\frac{e^{-ax}}{a} + \frac{e^{by}}{b} + C = 0$ , Where $C$ is constant of integration

$\frac{e^{-ax}}{a} - \frac{e^{by}}{b} + C = 0$ , Where $C$ is constant of integration

$\frac{e^{ax}}{a} + \frac{e^{-by}}{b} + C = 0$ , Where $C$ is constant of integration

$\frac{e^{ax}}{a} - \frac{e^{-by}}{b} + C = 0$ , Where $C$ is constant of integration

✅ Correct Option: 3

Related questions:

15 May Shift 1

For $y \neq 0$ , the particular solution of the differential equation $2ye^{xy}dx + (y - 2xe^{xy})dy = 0$ at the point (1, 1) is

15 May Shift 1

Match List-I with List-II

List-I	List-II
(Differential equation)	(Order and Degree)
(A) $\frac{d^3y}{dx^3} + y^2 + e^{dy/dx} = 0$	(I) order = 3, degree = 1
(B) $\left(\frac{d^2y}{dx^2}\right)^3 + \left(\frac{dy}{dx}\right)^2 + \frac{dy}{dx} + 1 = 0$	(II) order = 3, degree not defined
(C) $2x^2\frac{d^2y}{dx^2} - 3\left(\frac{dy}{dx}\right)^2 + y = 0$	(III) order = 2, degree = 3
(D) $\frac{d^3y}{dx^3} + 2\left(\frac{dy}{dx}\right)^2 + \frac{dy}{dx} = 0$	(IV) order = 2, degree = 1

Choose the correct answer from the options given below:

15 May Shift 2

The general solution of the differential equation $(x^2 - yx^2)dy + (y^2 + x^2y^2)dx = 0$ is:

CUET Mathematics 2025 13 May Shift 1 PYQs