Algebra > Matrices & Determinants
Easy
core
For a square matrix $A_{n \times n}$ (A) $|\operatorname{adj} \mathrm{A}|=|\mathrm{A}|^{\mathrm{n}-1}$ (B) $|\mathrm{A}|=|\operatorname{adj} \mathrm{A}|^{\mathrm{n}-1}$ (C) $\mathrm{A}(\operatorname{adj} \mathrm{A})=|\mathrm{A}|$ (D) $\left|\mathrm{A}^{-1}\right|=\frac{1}{|\mathrm{~A}|}$
✅ Correct Option: 2
Related questions:
2022: 10 Aug Shift 1
2025: 21 May Shift 1
2025: 15 May Shift 2
2026: 18th May Shift 1
2026: 19th May Shift 1
2025: 13 May Shift 2