CUET MathematicsGeometry > Mediumapplied100 cm2100 \mathrm{~cm}^{2}100 cm2253 cm225 \sqrt{3} \mathrm{~cm}^{2}253 cm2753 cm275 \sqrt{3} \mathrm{~cm}^{2}753 cm21003 cm2100 \sqrt{3} \mathrm{~cm}^{2}1003 cm2✅ Correct Option: 3Related questions:14 May Shift 1Consider the line r⃗=i^−2j^+4k^+λ(−i^+2j^−4k^)\vec{r} = \hat{i} - 2\hat{j} + 4\hat{k} + \lambda(-\hat{i} + 2\hat{j} - 4\hat{k})r=i^−2j^+4k^+λ(−i^+2j^−4k^) Match List-I with List-II List-IList-II(A) A point on the given line(I) (−121,221,−421)\left(\frac{-1}{\sqrt{21}}, \frac{2}{\sqrt{21}}, \frac{-4}{\sqrt{21}}\right)(21−1,212,21−4)(B) direction ratios of the line(II) (4,−2,−2)(4, -2, -2)(4,−2,−2)(C) direction cosines of the line(III) (1,−2,4)(1, -2, 4)(1,−2,4)(D) direction ratios of a line perpendicular to given line(IV) (−1,2,−4)(-1, 2, -4)(−1,2,−4) Choose the correct answer from the options given below:15 May Shift 2If the lines x−57=y+2−5=zλ\frac{x-5}{7} = \frac{y+2}{-5} = \frac{z}{\lambda}7x−5=−5y+2=λz and x1=y2λ=z3\frac{x}{1} = \frac{y}{2\lambda} = \frac{z}{3}1x=2λy=3z are perpendicular to each other, then λ\lambdaλ is equal to15 May Shift 2Consider the equation of the line r⃗=−i^+2k^+μ(4i^−j^+2k^)\vec{r} = -\hat{i} + 2\hat{k} + \mu(4\hat{i} - \hat{j} + 2\hat{k})r=−i^+2k^+μ(4i^−j^+2k^). Match List-I with List-II List-IList-II(A) It passes through the point(I) 4, -1, 2(B) Its direction ratios are(II) 421,−121,221\frac{4}{\sqrt{21}}, \frac{-1}{\sqrt{21}}, \frac{2}{\sqrt{21}}214,21−1,212(C) Its Cartesian form is(III) (-1, 0, 2)(D) Its direction cosines are(IV) x+14=y−1=z−22\frac{x+1}{4} = \frac{y}{-1} = \frac{z-2}{2}4x+1=−1y=2z−2 Choose the correct answer from the options given below: