CUET MathematicsCalculus > Mediumcore(A) - (I), (B) - (II), (C) - (III), (D) - (IV)(A) - (I), (B) - (III), (C) - (II), (D) - (IV)(A) - (II), (B) - (I), (C) - (III), (D) - (IV)(A) - (II), (B) - (IV), (C) - (III), (D) - (I)✅ Correct Option: 3Related questions:30 May Shift 1If xy+x2y=x3y+yxy + \frac{x^2}{y} = x^3y + yxy+yx2=x3y+y, then dydx\frac{dy}{dx}dxdy is equal to21 May Shift 1If x1+y+y1+x=0x\sqrt{1 + y} + y\sqrt{1 + x} = 0x1+y+y1+x=0, where ∣x∣<1,∣y∣<1|x| < 1, |y| < 1∣x∣<1,∣y∣<1 and x≠yx ≠ yx=y, then14 May Shift 2Match List-I with List-II List-IList-IIFunctionDerivative(A) y=sin−1x+sin−11−x2;∣x∣<1y = \sin^{-1} x + \sin^{-1} \sqrt{1 - x^2}; |x| < 1y=sin−1x+sin−11−x2;∣x∣<1(I) dydx=12y−1\frac{dy}{dx} = \frac{1}{2y-1}dxdy=2y−11(B) y=x+y,x+y>0 and y≠12y = \sqrt{x + y}, x+y > 0 \text{ and } y \neq \frac{1}{2}y=x+y,x+y>0 and y=21(II) dydx=10xloge10\frac{dy}{dx} = 10^x \log_e 10dxdy=10xloge10(C) y=log10x,x>0y = \log_{10} x, x > 0y=log10x,x>0(III) dydx=0\frac{dy}{dx} = 0dxdy=0(D) y=10xy = 10^xy=10x(IV) dydx=1xloge10\frac{dy}{dx} = \frac{1}{x \log_e 10}dxdy=xloge101 Choose the correct answer from the options given below: