CUET MathematicsCalculus > Mediumcoresin2asin(a+y)\frac{\sin ^{2} a}{\sin (a+y)}sin(a+y)sin2asin(a+y)sin2a\frac{\sin (a+y)}{\sin ^{2} a}sin2asin(a+y)sin(a+y)sina\frac{\sin (a+y)}{\sin a}sinasin(a+y)sin2(a+y)sina\frac{\sin ^{2}(a+y)}{\sin a}sinasin2(a+y)✅ Correct Option: 4Related questions:14 May Shift 1Which of the following are linear first order differential equations? (A) dydx+P(x)y=Q(x)\frac{dy}{dx} + P(x)y = Q(x)dxdy+P(x)y=Q(x) (B) dxdy+P(y)x=Q(y)\frac{dx}{dy} + P(y)x = Q(y)dydx+P(y)x=Q(y) (C) (x−y)dydx=x+2y(x - y)\frac{dy}{dx} = x + 2y(x−y)dxdy=x+2y (D) (1+x2)dydx+2xy=2(1 + x^2)\frac{dy}{dx} + 2xy = 2(1+x2)dxdy+2xy=2 Choose the correct answer from the options given below:19 May Shift 1Solution of the differential equation dydx=1+x2+y2+x2y2\frac{dy}{dx} = \sqrt{1 + x^2 + y^2 + x^2y^2}dxdy=1+x2+y2+x2y2 is : (Here CCC is an arbitrary constant)21 May Shift 1A integrating factor of the differential equation dydx+yx=1x2\frac{dy}{dx} + \frac{y}{x} = \frac{1}{x^2}dxdy+xy=x21, (x>0)(x > 0)(x>0) is equal to