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If [A]3×2[ B]x×y=[C]3×1[\mathrm{A}]_{3 \times 2}[\mathrm{~B}]_{\mathrm{x} \times \mathrm{y}}=[\mathrm{C}]_{3 \times 1}, then :

Solution

✅ Correct Option: 2

Matrix multiplication rule: The number of columns of the first matrix must equal the number of rows of the second matrix.

From [A]3×2[A]_{3 \times 2} and [B]x×y[B]_{x \times y}:

Columns of A=2A = 2 → Rows of B=x=2B = x = 2.

From [C]3×1[C]_{3 \times 1}:

Rows of A=3A = 3 → Rows of C=3C = 3.

Columns of B=y=1B = y = 1.

x=2,y=1\boxed{x = 2, y = 1}

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