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Ms. Sheela creates a fund of ₹ 1,00,0001,00,000 for providing scholarships to needy children. The scholarship is provided in the beginning of the year. This fund earns an interest of r%r \% per annum. If the scholarship amount is taken as ₹ 8,0008,000, then r=r=

Solution

✅ Correct Option: 2

Given:

  • Initial fund: ₹1,00,000₹1,00,000
    • Scholarship amount: ₹8,000₹8,000 (given at beginning of year)
    • Interest rate: r%r\% per annum

Since the scholarship is given at the beginning of the year, the remaining amount is:

₹1,00,000−₹8,000=₹92,000₹1,00,000 - ₹8,000 = ₹92,000

This amount must grow to ₹1,00,000₹1,00,000 by year-end:

₹92,000×(1+r100)=₹1,00,000₹92,000 \times (1 + \frac{r}{100}) = ₹1,00,000

Solving for rr:

1+r100=1,00,00092,0001 + \frac{r}{100} = \frac{1,00,000}{92,000}

r100=1,00,00092,000−1\frac{r}{100} = \frac{1,00,000}{92,000} - 1

r100=1,00,000−92,00092,000\frac{r}{100} = \frac{1,00,000 - 92,000}{92,000}

r100=8,00092,000\frac{r}{100} = \frac{8,000}{92,000}

r=100×8,00092,000r = 100 \times \frac{8,000}{92,000}

r=100×892r = 100 \times \frac{8}{92}

r=100×223r = 100 \times \frac{2}{23}

r=20023=81623%r = \frac{200}{23} = 8\frac{16}{23}\%

Therefore, r=81623%r = 8\frac{16}{23}\%

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