CUET MathematicsCalculus > Mediumapplied(A) - (I), (B) - (II), (C) - (III), (D) - (IV)(A) - (I), (B) - (III), (C) - (II), (D) - (IV)(A) - (I), (B) - (II), (C) - (IV), (D) - (III)(A) - (III), (B) - (IV), (C) - (I), (D) - (II)✅ Correct Option: 4Related questions:14 May Shift 2If y=xsinyy = x\sin yy=xsiny, then dydx\frac{dy}{dx}dxdy is:15 May Shift 2The value of k for which the function, defined by, f(x)={3x+4tanxx:x≠0k:x=0f(x) = \begin{cases} \frac{3x + 4 \tan x}{x} & : x \neq 0 \\ k & : x = 0 \end{cases}f(x)={x3x+4tanxk:x=0:x=0 is continuous at x=0x = 0x=0, is13 May Shift 2If x2−y2=1x^2 - y^2 = 1x2−y2=1, then which of the following is correct? (A) (x2−1)(dydx)2=x2(x^2 - 1)\left(\frac{dy}{dx}\right)^2 = x^2(x2−1)(dxdy)2=x2 (B) (x2−1)(d2ydx2)2=x2(x^2 - 1)\left(\frac{d^2y}{dx^2}\right)^2 = x^2(x2−1)(dx2d2y)2=x2 (C) (x2−1)3(d2ydx2)2=x2(x^2 - 1)^3\left(\frac{d^2y}{dx^2}\right)^2 = x^2(x2−1)3(dx2d2y)2=x2 (D) (x2−1)3(d2ydx2)2=1(x^2 - 1)^3\left(\frac{d^2y}{dx^2}\right)^2 = 1(x2−1)3(dx2d2y)2=1 Choose the correct answer from the options given below: