Two pipes A and B together can fill a tank in 40 minutes. Pipe A is twice as fast as pipe B. Pipe A alone can fill the tank in : Option 1: 1 hour Option 2: 2 hours Option 3: 80 minutes Option 4: 20 minutes

Answer: 1 hour. Solution: Make the PRT table: arrayl, c, c, c Person: & A + B & A & B \\ Rate: & & 2x & x \\ Time (mins): & 40 & & \\ Total Work: & & & \\ array Add the rates of the pipes working together: arrayl, c, c, c Person: & A + B & A & B \\ Rate: & 3x & 2x & x \\ Time (mins): & 40 & & \\ Total Work: & 120x & & \\ array Hence, time taken by Pipe A alone =120x/2x = 60 mins.

Arithmetic

Time & Work

Easy

applied

Two pipes A and B together can fill a tank in $40$ minutes. Pipe A is twice as fast as pipe B. Pipe A alone can fill the tank in :

$1$ hour

$2$ hours

$80$ minutes

$20$ minutes

✅ Correct Option: 1

Make the PRT table:

$\begin{array}{l|c|c|c} \text{Person:} & A + B & A & B \\ \hline \text{Rate:} & & 2x & x \\ \hline \text{Time (mins):} & 40 & & \\ \hline \text{Total Work:} & & & \\ \end{array}$

Add the rates of the pipes working together:

$\begin{array}{l|c|c|c} \text{Person:} & A + B & A & B \\ \hline \text{Rate:} & 3x & 2x & x \\ \hline \text{Time (mins):} & 40 & & \\ \hline \text{Total Work:} & 120x & & \\ \end{array}$

Hence, time taken by Pipe A alone $=\frac{120x}{2x} = 60$ mins.

2026: 21 May Shift 1

A pipe can fill a tank in 6 hours. Due to a leak in its bottom, it is filled in 7 hours. If the tank is full, then the time it will take to empty it because of the leak is:

2025: 14 May Shift 2

Three pipes A, B and C can fill a tank in 12 hours, 15 hours and 20 hours respectively. If A is open all the time and B and C are open for one hour each alternately, in how many hours will the tank be full?

2025: 15 May Shift 2

Two pipes A and B can fill a tank in 20 minutes and 30 minutes respectively. Both pipes A and B are opened together for some time and pipe B is turned off. If the tank is filled in 15 minutes, then after how many minutes pipe B is turned off?

2026: 22 May Shift 1

A tank is filled by three pipes with uniform flow. The first two pipes operating simultaneously fill the tank in the same time during which the tank is filled by the third pipe alone. The second pipe fills the tank 5 hours faster than the first pipe and 4 hours slower than the third pipe ,then the time required by the first pipe to fill the tank alone is :

2025: 30 May Shift 1

Two pipes A and B can fill a tank in 5 hours and 6 hours respectively. Pipe C can empty it in 12 hours. If all three pipes are opened together, then the time taken to fill the tank is:

2026: 19 May Shift 1

Three taps A, B and C can fill a tank in 12 minutes, 15 minutes and 20 minutes respectively. If tap A is opened all the time while tap B and C are opened for 1 minute each alternately such that tap B opened first, then the time taken to fill the tank is :

Two pipes A and B together can fill a tank in 404040 minutes. Pipe A is twice as fast as pipe B. Pipe A alone can fill the tank in :

Solution

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CUET Mathematics Past Year Questions (Topic-Wise)

Two pipes A and B together can fill a tank in $40$ minutes. Pipe A is twice as fast as pipe B. Pipe A alone can fill the tank in :