The solution set for the inequality $|5x-3| \le \dfrac{1}{5}$ is:

The solution set $\{x: x \in R, 3x-2 < x+2 \le 2x+6\}$ (Where $R$ is set of real numbers) is :

Which of the following inequalities are NOT correct?

(A) If $a > 1, b > 1,$ then $\log_b a + \log_a b \leq 2$

(B) For any real number $x, (9^x + 9^{1-x}) \geq 9$

(C) If $a,b,c$ are non-zero real numbers of the same sign, then $\left(\frac{a}{b} + \frac{b}{c} + \frac{c}{a}\right) \leq 3$

(D) If $a,b,c$ are three distinct real numbers, then $(a + b)(b + c)(c + a) \geq 8abc$

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The solution set of the inequation $4x + 3y > 5$ is

Match List-I with List-II

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Match the LIST-I with LIST-II

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All points lying inside the triangle formed by the points (5, 0), (-1, 2) and (1, 3) satisfy :

(A) $3x + 2y - 18 > 0$

(B) $3x + 2y > 0$

(C) $2x + y + 13 < 0$

(D) $2x - 3y - 12 < 0$

(E) $2x - 3y + 12 > 0$

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