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If the mean and variance of a binomially distributed random variable X are 4 and 2 respectively, then P(X=2)P(X = 2) is equal to

Solution

✅ Correct Option: 3

Mean np=4np = 4, Variance npq=2npq = 2. So q=12q = \frac{1}{2}, p=12p = \frac{1}{2}, n=8n = 8.

P(X=2)=(82)(12)2(12)6=28256=764P(X=2) = \binom{8}{2} (\frac{1}{2})^2 (\frac{1}{2})^6 = \frac{28}{256} = \frac{7}{64}.

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