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If A=[6−8−25]A = \begin{bmatrix} 6 & -8 \\ -2 & 5 \end{bmatrix} and A2−10A=CA^2 - 10A = C then C is equal to

Solution

✅ Correct Option: 2

A2=[36+16−48−40−12−1016+25]=[52−88−2241]A^2 = \begin{bmatrix} 36+16 & -48-40 \\ -12-10 & 16+25 \end{bmatrix} = \begin{bmatrix} 52 & -88 \\ -22 & 41 \end{bmatrix}. 10A=[60−80−2050]10A = \begin{bmatrix} 60 & -80 \\ -20 & 50 \end{bmatrix}. A2−10A=[−8−8−2−9]A^2 - 10A = \begin{bmatrix} -8 & -8 \\ -2 & -9 \end{bmatrix}.

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