Which of the following differential equations has y = x as one of its particular solution? Option 1: d^2y/dx^2 - x^2dy/dx + xy = x Option 2: d^2y/dx^2 - x^2dy/dx + xy = 0 Option 3: d^2y/dx^2 + x^2dy/dx + xy = 0 Option 4: d^2y/dx^2 + x^2dy/dx + 2xy = y

The answer is 'd^2y/dx^2 - x^2dy/dx + xy = 0'. View full solution:

CUET Mathematics - Which of the following differential equations has y = x as one of its particular solution? | PYQs + Solutions

CUET Mathematics 2026 21st May Shift 2

Calculus

Easy

common

$\dfrac{d^2y}{dx^2} - x^2\dfrac{dy}{dx} + xy = x$

$\dfrac{d^2y}{dx^2} - x^2\dfrac{dy}{dx} + xy = 0$

$\dfrac{d^2y}{dx^2} + x^2\dfrac{dy}{dx} + xy = 0$

$\dfrac{d^2y}{dx^2} + x^2\dfrac{dy}{dx} + 2xy = y$

✅ Correct Option: 2