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The differential equation of the family of curves y=asin⁡(bx+c)y = a \sin(bx + c), a and c are parameters, is :

Solution

✅ Correct Option: 1

Given y=asin⁡(bx+c)y=a\sin(bx+c).

dydx=abcos⁡(bx+c)\frac{dy}{dx}=ab\cos(bx+c)

d2ydx2=−ab2sin⁡(bx+c)=−b2y\frac{d^2y}{dx^2}=-ab^2\sin(bx+c)=-b^2 y.

Therefore d2ydx2+b2y=0\frac{d^2y}{dx^2}+b^2 y=0.

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