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Let [t][t] denotes the greatest integer ≤t\le t, then the value of [∫π3π/2x∣sin⁡x∣ dx]\left[\displaystyle\int_{\pi}^{3\pi/2} x|\sin x|\,dx\right] is:

Solution

✅ Correct Option: 2

On (π,3π/2)(\pi, 3\pi/2), sin⁡x≤0\sin x \le 0, so ∣sin⁡x∣=−sin⁡x|\sin x| = -\sin x and the antiderivative of −xsin⁡x-x\sin x is xcos⁡x−sin⁡xx\cos x - \sin x.

Evaluating from π\pi to 3π/23\pi/2 gives 1−(−π)=1+π≈4.141 - (-\pi) = 1+\pi \approx 4.14.

The greatest integer is 44.

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