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If A=[−220314]A = \begin{bmatrix}-2 & 2 & 0\\3 & 1 & 4\end{bmatrix} and B=[20−2716]B = \begin{bmatrix}2 & 0 & -2\\7 & 1 & 6\end{bmatrix} are two matrices such that −3A+5B+2C=0-3A + 5B + 2C = 0 then matrix C is equal to:

Solution

✅ Correct Option: 4

From −3A+5B+2C=0-3A + 5B + 2C = 0, C=12(3A−5B)C = \frac{1}{2}(3A - 5B).

Here 3A=[−6609312]3A = \begin{bmatrix}-6&6&0\\9&3&12\end{bmatrix} and 5B=[100−1035530]5B = \begin{bmatrix}10&0&-10\\35&5&30\end{bmatrix}.

Subtracting and halving gives [−835−13−1−9]\begin{bmatrix}-8&3&5\\-13&-1&-9\end{bmatrix}.

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