CUET Mathematics 2026 21st May Shift 2 PYQs

The area of the smaller region bounded by ellipse $\dfrac{x^2}{16}+\dfrac{y^2}{9}=1$ and the straight line $3x+4y=12$ is

The area of the region bounded by the line $3y = -2x + 7$, x-axis and the lines $x = 0$ and $x = 4$, is (in Sq. units)

The area (in sq. units) bounded by the curves $x = y^2$ and $x = y$ in the first quadrant is: