CUET Mathematics - Let y = f(x) be the solution curve of the differential equation dy/dx + 2y^2 = 0 if f(1) = 1, then f(2) is equal to | PYQs + Solutions

CUET Mathematics 2026 21st May Shift 2

Calculus

Medium

common

$-\dfrac{1}{4}$

$-\dfrac{1}{2}$

$\dfrac{1}{3}$

$\dfrac{1}{4}$

✅ Correct Option: 3

Related questions:

19th May Shift 1

Match List-I with List-II

List-I (Differential equation)	List-II (The sum of degree and order of the differential equation)
(A) $x\frac{d^2y}{dx^2} = \left(1+\left(\frac{dy}{dx}\right)^2\right)^{\frac{1}{3}}$	(I) 2
(B) $x\frac{d^2y}{dx^2} = \left(2-\frac{dy}{dx}\right)^{\frac{1}{7}}$	(II) 9
(C) $3+\frac{dy}{dx} = y+\frac{d^3y}{dx^3}$	(III) 4
(D) $\frac{dy}{dx} = x+3$	(IV) 5

Choose the correct answer from the options given below:

16 May Shift 1

The degree of the differential equation $\left(2 + \left(\frac{dy}{dx}\right)^2\right)^{\frac{3}{2}} = a^2 \frac{d^2y}{dx^2}$ is:

15th May Shift 1

If $p$ and $q$ are degree and order of the differential equation $\left(\dfrac{d^2y}{dx^2}\right)^3 - 2\left(\dfrac{dy}{dx}\right)^4 = 6$ respectively. Then the value of $2p+3q$ is

CUET Mathematics 2026 21st May Shift 2 PYQs

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