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Which of the following functions are strictly decreasing on (0,π2)\left(0, \dfrac{\pi}{2}\right)?

A. cos⁡x\cos x

B. −cot⁡x-\cot x

C. cos⁡2x\cos 2x

D. sin⁡x\sin x

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 1

On (0,π/2)(0,\pi/2): ddxcos⁡x=−sin⁡x<0\frac{d}{dx}\cos x = -\sin x < 0, so A decreases.

ddx(−cot⁡x)=csc⁡2x>0\frac{d}{dx}(-\cot x) = \csc^2 x > 0, so B increases.

ddxcos⁡2x=−2sin⁡2x<0\frac{d}{dx}\cos 2x = -2\sin 2x < 0, so C decreases.

sin⁡x\sin x increases, so D fails. Hence A and C.

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