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The random variable X has a probability distribution P(X)P(X) of the following form, where kk is some real number.

P(X=x)={k,if x=0k2,if x=1 or 20,otherwiseP(X=x) = \begin{cases}k, & \text{if } x=0\\\dfrac{k}{2}, & \text{if } x=1 \text{ or } 2\\0, & \text{otherwise}\end{cases}

On the basis of the above information, match List-I with List-II

LIST-ILIST-II
A. Value of kkI. 14\dfrac{1}{4}
B. P(X<2)P(X<2)II. 0
C. P(X>1)P(X>1)III. 12\dfrac{1}{2}
D. P(X>2)P(X>2)IV. 34\dfrac{3}{4}

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 2

Probabilities sum to 11: k+k/2+k/2=2k=1k + k/2 + k/2 = 2k = 1, so k=1/2k = 1/2 (III).

P(X<2)=1/2+1/4=3/4P(X<2) = 1/2 + 1/4 = 3/4 (IV).

P(X>1)=P(X=2)=1/4P(X>1) = P(X=2) = 1/4 (I).

P(X>2)=0P(X>2) = 0 (II).

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