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If the system of equation

λx+3y−z=4\lambda x + 3y - z = 4

x+2y+z=20x + 2y + z = 20

−λx+y+2z=−5-\lambda x + y + 2z = -5

does not possess a unique solution, then

Solution

✅ Correct Option: 2

A unique solution fails when the coefficient determinant vanishes.

Expanding, λ(4−1)−3(2+λ)−1(1+2λ)=3λ−6−3λ−1−2λ=−2λ−7\lambda(4-1) - 3(2+\lambda) - 1(1+2\lambda) = 3\lambda - 6 - 3\lambda - 1 - 2\lambda = -2\lambda - 7.

Setting this to zero gives λ=−7/2\lambda = -7/2.

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