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If y=axn+1+bx−ny = ax^{n+1} + bx^{-n}, then x2d2ydx2x^2 \dfrac{d^2y}{dx^2} is equal to

Solution

✅ Correct Option: 4

Differentiating twice, y′′=n(n+1)axn−1+n(n+1)bx−n−2y'' = n(n+1)ax^{n-1} + n(n+1)bx^{-n-2}.

Multiplying by x2x^2 gives n(n+1)(axn+1+bx−n)=n(n+1)yn(n+1)(ax^{n+1} + bx^{-n}) = n(n+1)y.

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