Which of the following differential equation represents the family of circles touching the x-axis at the origin ? Option 1: (x^2 - y^2)dy - 2xy dx = 0 Option 2: (x^2 + y^2)dy + 2xy dx = 0 Option 3: (x^2 - y^2)dx + 2xy dy = 0 Option 4: (x^2 + y^2)dy - 2xy dx = 0

The answer is '(x^2 - y^2)dy - 2xy dx = 0'. View full solution:

CUET Mathematics - Which of the following differential equation represents the family of circles touching the x-axis at the origin ? | PYQs + Solutions

CUET Mathematics 2023 23 May Shift 3

Calculus

Hard

$(x^2 - y^2)dy - 2xy\, dx = 0$

$(x^2 + y^2)dy + 2xy\, dx = 0$

$(x^2 - y^2)dx + 2xy\, dy = 0$

$(x^2 + y^2)dy - 2xy\, dx = 0$

✅ Correct Option: 1

Related questions:

22 May Shift 3

The differential equation $y = xp + \sqrt{x^2 p^3 + 4}$ where $p = \frac{dy}{dx}$ is :

(A) of order 1

(B) of degree 1

(D) of degree 3

Choose the correct answer from the options given below :

3 June Shift 1

If m and n are respectively the order and degree of the differential equation $(\frac{d^2y}{dx^2})^{2} + (\frac{dy}{dx})^3 + y= 4x$ , then the value of $m + n$ is:

29 May Shift 2

Match List-I with List-II:

List-I	List-II
Differential Equations	Degree/Order
(A) Degree of the differential equation $\frac{d^3y}{dx^3} + 2 \log x.y = 0$	(I) 3
(B) Order of the differential equation $\frac{d^4y}{dx^4} + \left(\frac{dy}{dx}\right)^4 + xy = 0$	(II) 2
(C) Degree of the differential equation $\left(\frac{d^4y}{dx^4}\right)^2 + \left(\frac{dy}{dx}\right)^3 + x^2y = 0$	(III) 1
(D) Order of the differential equation $\frac{d^3y}{dx^3} + y\left(\frac{dy}{dx}\right)^3 = 0$	(IV) 4

CUET Mathematics 2023 23 May Shift 3 PYQs

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