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If A and B are two events such that P(A)=310,P(B)=25P(A) = \dfrac{3}{10}, P(B) = \dfrac{2}{5} and P(A∪B)=35P(A \cup B) = \dfrac{3}{5}, then P(B∣A)+P(A∣B)P(B|A) + P(A|B) is:

Solution

✅ Correct Option: 3

P(A∩B)=P(A)+P(B)−P(A∪B)=3/10+4/10−6/10=1/10P(A\cap B) = P(A)+P(B)-P(A\cup B) = 3/10 + 4/10 - 6/10 = 1/10.

So P(B∣A)=(1/10)/(3/10)=1/3P(B|A) = (1/10)/(3/10) = 1/3 and P(A∣B)=(1/10)/(4/10)=1/4P(A|B) = (1/10)/(4/10) = 1/4.

Sum =1/3+1/4=7/12= 1/3 + 1/4 = 7/12.

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