CUET Mathematics - If the integral I = [log_e(log_e x)^2 + a/log_e x] dx = x log_e(log_e x)^2 + C, where C is constant of integration. Then the value of a is: | PYQs + Solutions

CUET Mathematics 2025 13 May Shift 2

Calculus

Medium

applied

-1

-2

✅ Correct Option: 4

Related questions:

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The value of the definite integral $I = \int_{-1}^{1} \frac{1}{1 + \sqrt{e^x}} dx$ is:

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$\int \frac{f'(x)}{f(x) \log_e[f(x)]} dx$ is equal to

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Match List-I with List-II

Choose the correct answer from the options given below:

CUET Mathematics 2025 13 May Shift 2 PYQs