The area bounded by $y = 3x + 1$, $x = 0$, $y = 0$ and $x = a$ is 8 Sq.units. Then value of $a$ (where $a > 0$) is

The area bounded by $x = \sqrt{9 - y^2}$, $x - y + 3 = 0$ and x-axis is :

Area bounded by the curves $y = x|x|$, $x = -1$, $x = 1$ is

The area of the region bounded between the line $x=3$ and the parabola $y^2=6x$ is:

The region bounded by curve $y = x|x|$, x-axis and lines $x = \pm 1$ is best represented graphically by :

The area enclosed by the curve $y^2 = 4ax$ and its latus-rectum is

The area of the region bounded by parabola $x^2 = 4y$, straight line $x = 2$ and $x$-axis, is