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The interval in which the f(x)=sin⁡x−cos⁡xf(x) = \sin x - \cos x, 0≤x≤2π0 \leq x \leq 2\pi is strictly decreasing is :

Solution

✅ Correct Option: 3

f′(x)=cos⁡x+sin⁡x=2sin⁡(x+π4)f'(x) = \cos x + \sin x = \sqrt{2}\sin\left(x + \frac{\pi}{4}\right).

f′(x)<0f'(x) < 0 when sin⁡(x+π/4)<0\sin(x + \pi/4) < 0, i.e., x+π/4∈(π,2π)x + \pi/4 \in (\pi, 2\pi).

So x∈(3π4,7π4)x \in \left(\frac{3\pi}{4}, \frac{7\pi}{4}\right).

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