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The value of ∫03∣2x−6∣dx\int_{0}^{3} |2x - 6| dx is :

Solution

✅ Correct Option: 3

For x∈[0,3]x \in [0, 3], 2x−6≤02x - 6 \leq 0, so ∣2x−6∣=6−2x|2x-6| = 6 - 2x.

∫03(6−2x)dx=[6x−x2]03=18−9=9\int_{0}^{3}(6 - 2x)dx = [6x - x^2]_{0}^{3} = 18 - 9 = 9.

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