CUET Mathematics 2026 18th May Shift 1 PYQs

The solution of the differential equation $\dfrac{dy}{dx} = \dfrac{x^2+xy+y^2}{x^2}$ for $x>0, y>0$ at $x=1, y=2$ is

Solution of the differential equation $\frac{dy}{dx} = x + xy - (1 + y)$ is:

The general solution of the differential equation $\dfrac{dy}{dx} = 1+x+y+xy$ is: (where $C$ is an arbitrary constant)

(A) $1+y = x+\dfrac{x^2}{2}+C$

(B) $\log_e|1+y|^2 = x^2+2x+C$

(C) $\log_e|1-y| = x-\dfrac{x^2}{2}+C$

(D) $\log_e|1+y| = x+\dfrac{x^2}{2}+C$

Choose the correct answer from the options given below: