CUET Mathematics - x^2 + 4/(x^2 + 3)(x^2 + 5) dx = u ^-1(xsqrt(3)) + v ^-1(xsqrt(5)) + c, where c is arbitrary constant, then value of 1/u^2 + 1/v^2 is equal to : | PYQs + Solutions | AfterBoards