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If the vertices of a triangle ABC are A(1,2,1)A(1, 2, 1), B(4,2,3)B(4, 2, 3) and C(2,3,1)C(2, 3, 1), then the equation of the median passing through the vertex AA, is

Solution

✅ Correct Option: 4

Midpoint of BCBC: D=(4+22,2+32,3+12)=(3,52,2)D = \left(\frac{4+2}{2},\frac{2+3}{2},\frac{3+1}{2}\right) = \left(3,\frac{5}{2},2\right).

Direction of median ADAD: (3−1,52−2,2−1)=(2,12,1)(3-1,\frac{5}{2}-2,2-1) = (2,\frac{1}{2},1).

Equation: x−12=y−21/2=z−11\frac{x-1}{2} = \frac{y-2}{1/2} = \frac{z-1}{1}, i.e., x−12=2y−4=z−1\frac{x-1}{2} = 2y-4 = z-1.

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