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If A and B are symmetric matrices of the same order, then which of the following are true?

(A) AB - BA is a skew symmetric matrix

(B) AB is a symmetric matrix

(C) AB is a scalar matrix

(D) AB + BA is a symmetric matrix

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 2

A symmetric matrix satisfies AT=AA^T = A. For transpose operations, (AB)T=BTAT(AB)^T = B^T A^T (order reverses).

Given that AA and BB are symmetric matrices of the same order, we have AT=AA^T = A and BT=BB^T = B.


For option (A), checking if AB−BAAB - BA is skew symmetric:

A matrix MM is skew symmetric if MT=−MM^T = -M.

(AB−BA)T(AB - BA)^T

=(AB)T−(BA)T= (AB)^T - (BA)^T

=BTAT−ATBT= B^T A^T - A^T B^T

=BA−AB= BA - AB

=−(AB−BA)= -(AB - BA)

Therefore, AB−BAAB - BA is skew symmetric. Option (A) is true.


For option (B), checking if ABAB is symmetric:

(AB)T(AB)^T

=BTAT= B^T A^T

=BA= BA

For ABAB to be symmetric, we need AB=BAAB = BA.

However, two symmetric matrices do not always commute.

Counterexample: A=[1002]A = \begin{bmatrix} 1 & 0 \\ 0 & 2 \end{bmatrix} and B=[2110]B = \begin{bmatrix} 2 & 1 \\ 1 & 0 \end{bmatrix}

Both are symmetric, but AB≠BAAB \neq BA.

Option (B) is false.


For option (C), checking if ABAB is a scalar matrix:

A scalar matrix has the form kIkI where II is the identity matrix.

The product of two symmetric matrices does not generally produce a scalar matrix.

Option (C) is false.


For option (D), checking if AB+BAAB + BA is symmetric:

(AB+BA)T(AB + BA)^T

=(AB)T+(BA)T= (AB)^T + (BA)^T

=BTAT+ATBT= B^T A^T + A^T B^T

=BA+AB= BA + AB

=AB+BA= AB + BA

Therefore, AB+BAAB + BA is symmetric. Option (D) is true.


Only statements (A) and (D) are true.

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