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Match List-I with List-II

List-IList-II
(A) ∫−11∣x∣dx=\int_{-1}^{1} \lvert x \rvert dx =(I) 3
(B) ∫−ππcos⁡x dx=\int_{-\pi}^{\pi} \cos x \, dx =(II) 1
(C) ∫−11(∣x∣−1)dx=\int_{-1}^{1} (\lvert x \rvert-1) dx =(III) 0
(D) ∫−11(∣x∣+1)dx=\int_{-1}^{1} (\lvert x \rvert+1) dx =(IV) -1

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 3

∣x∣|x| is even, so (A) =2∫01x dx=1=2\int_0^1 x\,dx=1, matching (II).

(B) [sin⁡x]−ππ=0[\sin x]_{-\pi}^{\pi}=0, matching (III).

(C) =1−∫−111 dx=1−2=−1=1-\int_{-1}^{1}1\,dx=1-2=-1, matching (IV).

(D) =1+2=3=1+2=3, matching (I).

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