Match List-I with List-II | List-I | List-II | |---|---| | (A) _-1^1 x dx = | (I) 3 | | (B) _-^ x dx = | (II) 1 | | (C) _-1^1 ( x -1) dx = | (III) 0 | | (D) _-1^1 ( x +1) dx = | (IV) -1 | Choose the correct answer from the options given below: Option 1: (A) - (I), (B) - (II), (C) - (IV), (D) - (III) Option 2: (A) - (II), (B) - (IV), (C) - (III), (D) - (I) Option 3: (A) - (II), (B) - (III), (C) - (IV), (D) - (I) Option 4: (A) - (I), (B) - (IV), (C) - (II), (D) - (III)

The answer is '(A) - (II), (B) - (III), (C) - (IV), (D) - (I)'. View full solution:

CUET Mathematics - Match List-I with List-II | List-I | List-II | |---|---| | (A) _-1^1 x dx = | (I) 3 | | (B) _-^ x dx = | (II) 1 | | (C) _-1^1 ( x -1) dx = | (III) 0 | | (D) _-1^1 ( x +1) dx = | (IV) -1 | Choose the correct answer from the options given below: | PYQs + Solutions

CUET Mathematics 2026 22nd May Shift 2

Calculus

Easy

common

(A) - (I), (B) - (II), (C) - (IV), (D) - (III)

(A) - (II), (B) - (IV), (C) - (III), (D) - (I)

(A) - (II), (B) - (III), (C) - (IV), (D) - (I)

(A) - (I), (B) - (IV), (C) - (II), (D) - (III)

✅ Correct Option: 3

Related questions:

3 June Shift 2

Match List-I with List-II

List-I	List-II
(A) $\int \dfrac{dx}{x^2 - 16}$	(I) $\dfrac{1}{8} \log \left\vert \dfrac{4 + x}{4 - x} \right\vert + c$ , Where C is an arbitrary constant,
(B) $\int \dfrac{dx}{x^2 + 16}$	(II) $\log \left\vert x + \sqrt{x^2 - 16} \right\vert + c$ , Where C is an arbitrary constant,
(C) $\int \dfrac{dx}{16 - x^2}$	(III) $\dfrac{1}{8} \log \left\vert \dfrac{x - 4}{x + 4} \right\vert + c$ , Where C is an arbitrary constant,
(D) $\int \dfrac{dx}{\sqrt{x^2 - 16}}$	(IV) $\dfrac{1}{4} \tan^{-1} \left( \dfrac{x}{4} \right) + c$ , Where C is an arbitrary constant,

Choose the correct answer from the options given below:

29th May Shift 2

The value of $\int_0^{\pi/2} \frac{\cos x}{\cos\frac{x}{2}+\sin\frac{x}{2}}\,dx$ is

30 May Shift 2

$\int (x^4 + x^2 + 1)d(x^2)$ is equal to: (where c is an integration constant)