CUET Mathematics - Let e^ y + e^ y + yx^2 + |x| + C = 0, where C R_0 be a particular solution of the differential equation x(e^2y - 1)dy + (x^2 - 1)e^ydx = 0 and passes through the point (1, 1). The value of ( + + + - C) is | PYQs + Solutions

CUET Mathematics 2025 14 May Shift 1

Calculus

Hard

applied

$e - 1$

$e^2 - 1$

$e + \frac{1}{e}$

$\frac{1}{e}$

✅ Correct Option: 3

Related questions:

22 May Shift 2

Match List-I with List-II

List-I	List-II
Differential Equation	Order and Degree
(A) $\left(\frac{d^2y}{dx^2}\right)^2 = e^x\left(\frac{dy}{dx}\right)^4 + 1 = 0$	(I) order = 1 and degree = 2
(B) $\left(\frac{dy}{dx}\right)^2 + xy = 0$	(II) order = 2 and degree = 1
(C) $\left(1 + \frac{dy}{dx}\right)^{3/2} = 4\left(\frac{d^2y}{dx^2}\right)^2$	(III) order = 2 and degree = 2
(D) $\sqrt\frac{d^2y}{dx^2} + 1 = \frac{dy}{dx}$	(IV) order = 2 and degree = 4

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30 May Shift 1

The solution of the differential equation $\log_e\left(\frac{dy}{dx}\right) = 5x + 2y$ is given by

3 June Shift 1

Match List-I with List-II

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CUET Mathematics 2025 14 May Shift 1 PYQs